Lim x->0 & x>0 (1/sin x)
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Lim x->0 & x>0 (1/sin x)

[From: ] [author: ] [Date: 11-05-26] [Hit: ]
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I cannot manage to find the answer to this question, i would really appreciate ur help

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The limit does not exist (or is infinite, depending on your notation).

Since sin(0)=0 and sinx is continuous with sinx > 0 for x>0, we have that
lim [x→0+] sinx = 0+ (by which I mean the limit is 0 and the values are all positive as you approach).
Therefore
1/sinx → +∞.

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keywords: Lim,sin,amp,gt,Lim x->0 & x>0 (1/sin x)
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