Calculus - limits questions

The graph of f(x) is given(refer to question 1 of the following website). How would you do the last 3 limits of question 1? The last 3 are:

lim h->0+ [f(h-2)-f(-2)]/h = negative infinity

lim h->0+ [f(h+2)-f(2)]/h = infinity

lim h-> 0- [f(1+h)-f(1)]/h = -1

http://66.51.172.120/fharris/Math116/2010FallTests&Keys/11602MTKey.pdf

Please explain. Thank you so much!

1) f(h-2) as h tend to 0+ = 1
f(-2) = 2
f(h-2) - f(-2) = 1-2 = -1
so [f(h-2)-f(-2)]/h = -1 / extreme small number = negative infinity.

2) f(h+2) as h tend to 0+ = 1
f(2) = -1
f(h+2)-f(2) = 2
[f(h+2)-f(2)]/h = 2 / extreme small number = infinity

3)f(1+h) - f(1) = -2 + 2 = extreme small but positive number
h tend to 0- = extreme small but negative number
[f(1+h)-f(1)]/h = small positive number / small negative number = -1
same as x/-x = -1