GRADE 11 MATH Help Please!
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GRADE 11 MATH Help Please!

[From: ] [author: ] [Date: 11-05-27] [Hit: ]
We can check by finding the middle term and we get 9x - 2x = 7x.3x - 1-just to add to the above for 3x-1 ,......
I need help with the following question...

I need to simplify these 2 questions....

1. 6x^2+7x-3 over 2x+3

2. 3x(3x+1)-(1+9x^2)

-
1.) (6x²+7x-3)/(2x+3)
→ [(2x+3)(3x-1)]/(2x+3)
→ 3x-1
Solution: 3x-1

2.) 3x(3x+1)-(1+9x²)
→ 9x²+3x-1-9x²
→ 3x-1
Solution: 3x-1

-
(6x^2 + 7x - 3)/(2x + 3)

Start by noting the denominator cannot be factored so to simplify the expression (2x + 3) must be a factor of (6x^2 + 7 - 3). So, if we use the foil method we get at first

(2x + 3)(

Now to get 6x^2 having 2x as one of its factors the other factor is 3x and we get

(2x + 3)(3x

Now we need to get - 3 with a known factor of + 3 so the other factor must be - 1. so we think the answer is

(2x + 3)(3x - 1)

We can check by finding the middle term and we get 9x - 2x = 7x.

Now we can cancle the 2x + 3 from top and bottom and get 3x - 1 as the answer

3x(3x+1) - (1 + 9x^2)

9x^2 + 3x - 1 - 9x^2

3x - 1

-
just to add to the above for 3x-1 , x = 1/3
1
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