Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 3 hours. How much time would it take for them to mow the lawn together? pls show work? thanks!
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Jack= 1/2 Marilyn
Marilyn = 2 Jack
1 Jack = 6 hrs.
1 Jack + 1 Marilyn = 3 Jack
So 3 Jack would get a 1 Jack 6 hour job done in... 6/3= 2 hours
Marilyn = 2 Jack
1 Jack = 6 hrs.
1 Jack + 1 Marilyn = 3 Jack
So 3 Jack would get a 1 Jack 6 hour job done in... 6/3= 2 hours
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I'm not sure if I'm answering this right haha. I'm much better with equational problems ;) but I will give it my best shot. Hopefully, others will come up with the same answer....
Let's take a look at this logically. Jack mows his lawn in six hours. Marilyn in three hours. Now, I go by solving things logically and through guess and chance (educational guess and chance that is). Let's ask what happens if they both mow the grass for one hour... ok that means that Jack mowed 1/6 of however big the yard is during that time. Marilyn mowed 1/3 of the entire yard during that time. If you combine it, it will not equal one. So let's go to two. In two hours, Jack would have mowed 2/6 or 1/3 of the yard. In two hours, Marilyn would have mowed 2/3 of the yard. COmbine 1/3 to 2/3 and you have 3/3 which equals one, which is 100% of the yard.
So in two hours Jack and Marilyn would have both completed mowing the same lawn together....
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I so hope I answer this right. The thing is, I answer word problems logically. Most of the times this works, sometimes it doesn't. I still have to figure out how to see a word problem and translate it into an equational problem :) So if you used my answer and got it right! Thank Goodness and congratz! If I'm wrong, than I'm really sorry... Hopefully, there will be others who answer and get the correct answer if I answer it wrong.
Let's take a look at this logically. Jack mows his lawn in six hours. Marilyn in three hours. Now, I go by solving things logically and through guess and chance (educational guess and chance that is). Let's ask what happens if they both mow the grass for one hour... ok that means that Jack mowed 1/6 of however big the yard is during that time. Marilyn mowed 1/3 of the entire yard during that time. If you combine it, it will not equal one. So let's go to two. In two hours, Jack would have mowed 2/6 or 1/3 of the yard. In two hours, Marilyn would have mowed 2/3 of the yard. COmbine 1/3 to 2/3 and you have 3/3 which equals one, which is 100% of the yard.
So in two hours Jack and Marilyn would have both completed mowing the same lawn together....
...
...
I so hope I answer this right. The thing is, I answer word problems logically. Most of the times this works, sometimes it doesn't. I still have to figure out how to see a word problem and translate it into an equational problem :) So if you used my answer and got it right! Thank Goodness and congratz! If I'm wrong, than I'm really sorry... Hopefully, there will be others who answer and get the correct answer if I answer it wrong.
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Let h = hours it takes if they worked together
then
h(1/3 + 1/6) = 1
multiplying both sides by 18:
h(6 + 3) = 18
9h = 18
h = 2 hours
then
h(1/3 + 1/6) = 1
multiplying both sides by 18:
h(6 + 3) = 18
9h = 18
h = 2 hours
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Jack mows 1/6 of his lawn in an hour, Marilyn mows 1/3. So the solution to x/6+x/3 = 1, where x is the amount of time in hours, is when x = 2.
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If they worked two hours total, she would do 2/3 of a lawn ( 2 hrs/3 hours) and he would do 2/6 of a lawn (2 hrs/6 hrs).
So 1/3 + 2/3 = 1,
2 Hours
So 1/3 + 2/3 = 1,
2 Hours