How do I solve (7x + 2)^2 – 5x[–3(x + 2)]
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How do I solve (7x + 2)^2 – 5x[–3(x + 2)]

[From: ] [author: ] [Date: 11-06-14] [Hit: ]
Then go to -3(X+2).Now multiply -5X*(-3X-6),Put this expression together with the one at the top so you have 49X^2+28X+4+15X^2+30X.Simplify that by adding the like expressions.64x^2 + 58x + 4 -You cant solve that since its not an equation, but you can simplify it as it was done above.......
I need the answer as well. Thanks.

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Start with (7x +2)*(7x+2).
Multiply the 7X by (7X+2) to get 49X^2+14X
Then multiply 2 by (7X+2) to get 14X+4
Put those expressions together to get 49X^2+14X+14X+4 which is 49X^2+28X+4

Then go to -3(X+2). Multiply the -3 by each to get -3X-6
Now multiply -5X*(-3X-6), which is 15X^2+30X

Put this expression together with the one at the top so you have 49X^2+28X+4+15X^2+30X. Simplify that by adding the like expressions. 64X^2+58X+4 is your answer

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(7x + 2)^2 - 5x(-3(x + 2))
49x^2 + 28x + 4 - 5x(-3(x + 2))
49x^2 + 28x + 4 - 5x(-3x - 6)
49x^2 + 28x + 4 + 15x^2 + 30x
64x^2 + 58x + 4 <===ANSWER

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You can't solve that since it's not an equation, but you can simplify it as it was done above.
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