Help! Probability question

If you toss a coin three times, what is the probability that you get.
1. Heads,Tales,Heads
2. No Tails
3. Only one Tail

Can you show the solution on how you did it?

Make a list of all possible events. I'll call heads 'h' and tails 't'. Here are the possible events:
hhh
hht
hth
htt
thh
tht
tth
ttt

Now we just count how many times the event occurs, and how many total events there are.
Question 1. hth appears 1 time out of 8 possible events, so the answer is 1/8
question 2. no tails means hhh. that happens 1/8
question 3. that happens 3 times out of 8. 3/8

E: toss a coin three times.

Ω = {hhh, hht, hth, htt, tth, tht, thh, ttt}

1)

P(hth) = P(h)*P(t)*P(h) = (1/2)*(1/2)*(1/2) = 1/8

2)

P(hhh) = P(h)*P(h)*P(h) = (1/2)*(1/2)*(1/2) = 1/8

3)

P(hht⋃hth⋃thh) = P(hht) + P(hth) + P(thh) = 1/8 + 1/8 + 1/8 = 3/8

To get them in order in problem 1
1/2 x 1/2 x 1/2 = 1/8
2. 1/2 x 1/2 x 1/2 = 1/8
3. 1/4

you could draw a tree diagram, with branches of heads and tails.

none of em its either gonna be on on side or night