How to write an equation in y= mx+b form of the line that is described

I'm stuck on a math problem.

"Write an equation in the form y=mx+b of the line that is described. The y-intercept is 5 and the line is parallel to the line whose equation is 3x+y=6."

How do I find the other equation? I know the y-intercept is (0,5) but how do i find the slope of this unknown equation?

parallel lines have the same slope. So if the line is parallel to the line with equation 3x+y=6, then one way to find slope is start by writing the given equation in y=mx+b form so you can determine its slope

for 3x+y=6, subtract 3x from both sides (write right side in descending order) to get

y = -3x + 6

this line has a slope of -3, so any line parallel to it also has slope of -3.

thus, you can write the equation of the line you want using -3 for slope and 5 for the intercept:

y = -3x + 5


hope that helps.

If the line is parallel to 3x + y = 6 ==> y = -3x +6 then it has the same slope, that is -3

The form y = mx + b, m is the slope and b the y-intercept... then m=-3 and b = 5

Then the equation is: y = -3x+5 Ok!

y = -3x + 6
y = -3x + 5 => answer

Edit: the parallel lines have the same slope.