please fill in the missing value x^2+8x+__
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16.
(x+4)(x+4) = x^2+8x+16
(x+4)(x+4) = x^2+8x+16
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It's not impossible, actually.
In order to complete the square, you must first have 1 as your a term (the number next to the x^2). Fortunately, the a term is already 1 in this problem so you can overlook this step!
Next, you must find the value of HALF the b term (the number next to the x). In this case, the b term is 8, so half of 8 is 4.
Lastly, you add the square of the number that you just obtained to the equation (To keep things simple, just write this number as 4^2) which gets you:
x^2+8x+4^2
Next you factor it, which is easy because all you need to do is take the square root of the a term and the c term (the number you just found), and write them as a binomial that is squared:
(x+4)^2
And that is your answer. Hope this helps!
In order to complete the square, you must first have 1 as your a term (the number next to the x^2). Fortunately, the a term is already 1 in this problem so you can overlook this step!
Next, you must find the value of HALF the b term (the number next to the x). In this case, the b term is 8, so half of 8 is 4.
Lastly, you add the square of the number that you just obtained to the equation (To keep things simple, just write this number as 4^2) which gets you:
x^2+8x+4^2
Next you factor it, which is easy because all you need to do is take the square root of the a term and the c term (the number you just found), and write them as a binomial that is squared:
(x+4)^2
And that is your answer. Hope this helps!
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I hope you realize this problem is impossible because it's incomplete.