Geometry review help

line contains the points (3, -4) and (5, 2). Another line graphed in the same coordinate plane contains the points (0, -2) and (6, -4). Based on the slopes of these lines are they parallel, perpendicular or neither?

Write the equation of a line in slope-intercept form that is parallel to the line 2x-5y= -8 and containing point (-5, 0).

Write the equation of a line perpendicular to the line x+2y=5 and containing the point (-3, -1).

1)
slope of line 1 = 2 - (-4) / 5 - 3 = 3
slope of line 2 = -4 - (-2) / 6 - 0 = -1/3

the slopes are negative reciprocals of each other, so the lines are perpendicular

2) put the given line in slope-intercept form first:
-5y = -2x - 8
y = (2/5)x + 8/5
parallel means the same slope, so equation is:
y = (2/5)x + b
use the given point to solve for b:
0 = (2/5)(-5) + b
b = 2
so equation is:
y = (2/5)x + 2

3) put the given line in slope-intercept form first:
2y = -x + 5
y = (-1/2)x + 5/2
perpendicular means a slope that is negative reciprocal of the slope:
y = 2x + b
use the given point to solve for b:
-1 = 2(-3) + b
b = 5
so equation is:
y = 2x + 5

a. slope of first two points is 2- -4/ 5-3 6/2 = 3
slope of 2nd two points -4- -2/6-0 -2/6 -1/3

lines are perpendicular with - reciprocal slopes.

b. slope intercept needs x to be zero.... for point .....so we need y-y= m x- x

parallel is same slope

y-0 = 2/5 (x- -5)

y= 2/5x + 2

c.

y- -1 = 2(x- -3)

y+1=2x+6
y=2x+5

1. perpendicular

2. y= 2/5x+2

3. y= 2x+5