Are you good in college math problems if so may I please get some help in these problems., please thankyou
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Are you good in college math problems if so may I please get some help in these problems., please thankyou

[From: ] [author: ] [Date: 11-07-04] [Hit: ]
the body begins to cool. It has been determined experimentally that the constant in Newtons Law of Cooling is approximately k = 0.1947, assuming time is measured in hours. Suppose that the temperature of the surroundings is 70°F.If the temperature of the body is now 78°F,......
first question: A Chicken is taken from an oven when its temperature has reached 185°F and is placed on a table in a room where the temperature is 64°F. When will the turkey cool to 100°F?

Second question: Also another question Newton's Law of Cooling is used in homicide investigations to determine the time of death. The normal body temperature is 98.6°F. Immediately following death, the body begins to cool. It has been determined experimentally that the constant in Newton's Law of Cooling is approximately k = 0.1947, assuming time is measured in hours. Suppose that the temperature of the surroundings is 70°F.If the temperature of the body is now 78°F, how long ago was the time of death?

I am totally confused on how to approach these two questions. Any help is greatly appreciated.

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1st : the ' chicken ' change to a ' turkey ' after removing from oven...hmmmm

2nd : Newton's Law of Cooling is dT / dt = k ( T - Ta ) , Ta = ambient temp

3rd: in #1 Ta = 64 , T(0) = 185...solve the differential equation ..

answer will contain the parameter k since not enough info given

4th : in #2 Ta = 70 , T(0) = 98.6 , k given , solve for T , then let T = 78 and find t value..

person was thus killed t hours ago...you certainly can do these computations

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I am very bad, sorry
1
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