How do I solve for y for this question

I have my differential equation down to e^y = 0.5e^(2x) + C where C is a constant, and I need to solve for y.

How do I go about it??? Thanks :)

e^y = 0.5 e^(2x) + c

. . . take the natural log of each side

ln(e) * y = ln(0.5 e^(2x) + c)

. . . ln(e) = 1

y = ln( 0.5 e^(2x) + c )

Just take the natural log of both sides!
ln(e^y)= ln(0.5e^(2x)+C)
y=ln(0.5e^(2x)+C)

e^y = 0.5e^(2x) + C
take ln of both sides
=> y = ln(0.5e^2x + C)