A problem of Sari Shoes,and handbag

when i walked into the shop in New Market i had altogether rs.140/- in purse.when i walked out i didint have a single paise,instead i had a sari,a pair of shoes and a handbag.
the sari cost Rs 90/- more than the handbag and the sari and the handbag cot together Rs.120/- more than the pair of shoes.How much did i pay for each item
answer given is shoes:10/-,handbag Rs:20/-, sari:110/-
pls explain in detail with steps.

Let H be the cost of hand bag. So cost of saree is H+90.
Also, sari and handbag cost together 120 more than Shoe. That means H+H+90 = Sh+120, where Sh is shoe cost
2H+90=Sh+120 ----> Equation1
But H+Sh+Saree=140
H+H+90+Sh=140
2H+90+Sh=140
But from equation 1, 2H+90=Sh+120

so..... Sh+120+Sh=140
2Sh=20
Sh=10
Putting this value in equation1, H=20
Cost of saree= 110
Cost of handbag is 20
Cost of Shoe is 10

I think it's easier with symbols.

Let x be the cost of the sari, y be the price of the shoes and z be the price of the handbag.

First, you know that x + y + z = 140 because all the Rs were spent.

"the sari cost 90 more than the handbag" translates to:

x = z + 90

"the sari and the handbag together cost 120 more than the shoes" translates to:

x + z = y + 120

The entire cost can be written as:

(x + z) + y = 140

But the equation above says that x + z = y + 120, so you can replace (x + z) with (y + 120):
(y + 120) + y = 140
y + y + 120 = 140 .... you can add in any order
y + y = 20 ..... subtract 120 from both sides "equals minus equals are equal"

So y is obviously 10, and since x+y+z = 140, then x+z alone must be 130

x + z = 130.

Now remember that x = z + 90, so that
(z + 90) + z = 130
z + z + 90 = 130 .... again, you can add in any order
z + z = 40 .... subtract 90 from both sides
z = 20

Now x + y + z = x + 10 + 20, but that's equal to:

x + 10 + 20 = 140
x + 30 = 140
x = 110

That's it. The sari cost x=100, the shoes y=10 and the handbag z=20.