Given that tan t = -1 and that the terminal side of t lies in Quadrant IV, find sin t

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Given that tan t = -1 and that the terminal side of t lies in Quadrant IV, find sin t

[From: ] [author: ] [Date: 11-08-13] [Hit: ]

Ans-arctan(-1) = 3π/4, 7π/4, the latter is in QIV.sin(7π/4) = -1/√2 ≈ -0.......

Thanks for your help!

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sin t = - (√2)/2

t's reference angle is 45º...in the fourth quadrant, that is 315º

@Σ

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sin(t)=-1/sqrt(2) .............Ans
because in IV- Quadrant sin(t) and tan(t) are negative and t = -45 degrees
sin(-45 degrees) = -1/sqrt(2) .......Ans

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arctan(-1) = 3π/4, 7π/4, the latter is in QIV.

sin(7π/4) = -1/√2 ≈ -0.707

1

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