Trig problem with square root HELP?!

tan(2x) = - root 3 <--- - ((3)^(1/2))

All I've got is
(2tanx)/(1-tan^2x)=- ((3)^(1/2)) using the property, but now what?

thanks

I'll solve in degrees, you can convert to radians if you need to.

You don't need to use double angle formula. Just find 2x, and then halve it:

tan(2x) = -sqrt(3)

Now you should know that tan(60 degrees) = sqrt(3)
=> the 2nd and 4th quadrant corresponding angles have tan of -sqrt(3)
=> tan(120 degrees) and tan(300 degrees) = -sqrt(3)
or to put into a single equation
tan(120 + 180n degrees) = -sqrt(3) ... for any integer n
=> 2x = 120 + 180n degrees ... for any integer n
=> x = 60 + 90n degrees ... for any integer n