Stoichiometry/Limiting Reagent question

If 60 mL of Vinegar contains 0.049 mol of HC2H3O2, how many grams of Sodium Hydrogen Carbonate (NaHCO3) will react with this amount of acid?

Having a hard time getting this one started..could someone walk me through it?

You're only given the amount of one reactant, so it can't be a limiting reagent question. The volume of vinegar is of no interest.

HC2H3O2 + NaHCO3 → NaC2H3O2 + CO2 + H2O

(0.049 mol HC2H3O2) x (1/1) x (84.0068 g NaHCO3/mol) = 4.1 g NaHCO3