(√6mn)^5
solve:
√2y+1=7
y=
multiply
(4+ √3)(4- √3)
These are the only 3 that im stuck on out of 24 please help :0)
solve:
√2y+1=7
y=
multiply
(4+ √3)(4- √3)
These are the only 3 that im stuck on out of 24 please help :0)
-
√6 means 6 to the 1/2 power and 6^5/2 power means the square root of 6^5. When you "exponentize" an exponent, you multiply the exponents:
(6^1/2 mn)^5
6^5/2 m^5 n^5
√(6^5) m^5 n^5
√6√6√6√6√6 m^5 n^5
36m^5n^5√6
You get rid of a radical sign by squaring it so make sure only the radical is on one side of the equation:
√2y+1=7
√2y=7-1
√2y=6
2y=6^2
2y=36
y=36/2
y=18
(4+√3)(4-√3)
16-4√3+4√3-√3√3
16-3
13
(6^1/2 mn)^5
6^5/2 m^5 n^5
√(6^5) m^5 n^5
√6√6√6√6√6 m^5 n^5
36m^5n^5√6
You get rid of a radical sign by squaring it so make sure only the radical is on one side of the equation:
√2y+1=7
√2y=7-1
√2y=6
2y=6^2
2y=36
y=36/2
y=18
(4+√3)(4-√3)
16-4√3+4√3-√3√3
16-3
13