Find the directional derivative of f(x,y) = sin(x+2y) at the point (-3, 2) in the direction theta = pi/6.
So: gradient f =
gradient f(-3,2) =
What I am stuck on is the theta. I need to find the directional derivative and I cannot figure it out.
I know that the (magnitude of gradient f)*(magnitude of unit vector = 1)*(cos(theta)) = directional derivative, however it is not the answer. If someone could please help that would be great.
So: gradient f =
gradient f(-3,2) =
What I am stuck on is the theta. I need to find the directional derivative and I cannot figure it out.
I know that the (magnitude of gradient f)*(magnitude of unit vector = 1)*(cos(theta)) = directional derivative, however it is not the answer. If someone could please help that would be great.
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Given θ, the (unit) direction vector is .
In this case, since θ = π/6, the desired unit vector is <√3/2, 1/2>.
It looks like you know what to do from here...
In this case, since θ = π/6, the desired unit vector is <√3/2, 1/2>.
It looks like you know what to do from here...