Setup a Differential equation with water tanks

Water leaks from a vertical cylindrical tank through a small hole in its base at a rate proportional to the square root of the volume of water remaining. the tank initially contains 175 liters and 23 liters leak out during the first day.

I would just like to know what is the differential equation I need to setup. Thanks

Let V(t) represent the volume of water in the tank at time t.

dV/dt = c√(V) for some constant c

dV/dt = k sqrt (V)

dV/dt * 1 / sqrt(V) = k

[ 1 / sqrt(V) ] dV = [ k ] dt