Solve the definite Integral

1
∫
-1 e^-iπx dx=?

can someone please solve this? step by step solution please someone. thanks.

thanks much!

∫(x = -1 to 1) e^(-iπx) dx
= (1/(-iπ)) e^(-iπx) {for x = -1 to 1}
= (1/(iπ)) [e^(iπ) - e^(-iπ)]
= (1/(iπ)) (-1 - (-1))
= 0.

I hope this helps!