A probability experiment is conducted in which the sample space of the experiment

is s = {1,2,3,4,5,6,7,8,9,10,11,12}. let event E = {2,3,4,5,6,7}, event F = {5,6,7,8,9}, event G= {9,10,11,12}, and event H = {2,3,4}. Assume that each outcome is equally likely.

Find P(F or G) by counting the number of outcomes in F or G. Determine P (F or G) using the General Addition Rule.

How many ways can the event F or G occur? Add them up and subtract the intersection of the sets (they are not mutually exclusive). Divide this by the cardinality of your sample space, and you're good.You should get 8/12=2/3. Stay in school.