There are 51 students in a certain class. The number of females is 5 less than three times the number of males

Let the no. of males be x.
No. of females -> 3x - 5

3x - 5 + x = 51
4x - 5 = 51
4x = 56
x = 14

The number of males is 14.

No. of females = 14 * 3 - 5
= 42 - 5
= 37

The number of females is 37

I hope this helps. :)

There are 51 students in a certain class.
The number of females is 5 less than three times the number of males?

let x = males
then y = females = 3x - 5

therefore x + y = 51

now sub. y = 5 - 3x in the above equation
x + 3x - 5 = 51
x + 3x = 51 + 5
4x = 56
x = 56 / 4
x = 14 => there are 14 males

plug x = 14 into x + y = 51 to find y = females

14 + y = 51
y = 51 - 14
y = 37

males = 14
females = 37

CHECK THE ANSWER:
x = 14 = males
y = 37 = females

x + y = 51
14 + 37 = 51
51 = 51

Algebra ******* Rocks!

M + F = 51
M =51 - F

--> F = 3M - 5, F=3(51 - F) - 5, F= 153 - 3F - 5, F= -3F +148, 4F = 148, F=37

--> 37 = 3M - 5, 42 = 3M, 14 = M

M = 14
F = 37

Number of males—m:
3m - 5 + m = 51
4m = 56
m = 14

Number of females:
= 3(14) - 5
= 42 - 5
= 37

Answer: 14 males & 37 females

M + F = 51
F = 3M - 5
M = 14
F = 37

14 boys and 37 girls