F(x)= abs(x-2), find all values of x such that f(x) > 1

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f(x)= abs(x-2), find all values of x such that f(x) > 1

Given: |x - 2| > 1

Case 1: x - 2 > 1

x > 3

Case 2: -(x - 2) > 1

-x + 2 > 1

-x > -1

x < 1

Therefore, (-inf, 1) U (3, + inf)