Use rational exponents to simplify

^3√(x^-9)

Also, what is this problem?

Simplify by taking roots of the numerator and the denominator.
^3√(729/343)

I am completely stuck on these problems!

CubeRoot (x^(-9))

[x^(-9)]^(1/3)...............power to power, MULTIPLY THE EXPONENTS

.........................-9(1/3) = -3

x^(-3)..........................Negati… Exponent Means to Invert

..1
****.................ANSWER
x^3

Even thought the numbers are bigger the problem is easier because these numbers are Perfect Cubes

9^3 = 729
7^3 = 343

Cube root of (729/343)

(729/343)^(1/3)

9
**.....................ANSWER
7

unable to get the question...type clearly..i will answer it ....