Estimating instananeous rates of change from equations
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Estimating instananeous rates of change from equations

[From: ] [author: ] [Date: 11-10-17] [Hit: ]
14 m/s-B)Rate is answer to part a in the equation rate= -4.A) use a graphing calculator or kinematic equations solving for time without velocity final.......
A diver is on the 10 m platform, preparing to perform a dive. The diver's height above the water, in metres, at time t can be modelled using the equation h(t) = 10 + 2h - 4.9t^2

(a) determine when the diver will enter the water

(b) estimate the rate at which the diver's height above the water is changing as the diver enters the water

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2h should be 2t, otherwise it does not make sense, it represents the constant velocity

a) solve h(t) = 0

10 + 2t - 4.9t² = 0

t = 1.647 s

b) take the derivative and plug in 1.647 s

dh/dt = 2 - 9.8 t
dh/dt = 2 - 9.8 (1.647 ) = -14.14 m/s

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B)Rate is answer to part a in the equation rate= -4.9t+2 (derivative of equation)
A) use a graphing calculator or kinematic equations solving for time without velocity final.
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