With the slope -6 THROUGH (2-1).
This one sort of throws me off. I am not sure if I do the m= y2-y1 over x2-x1, because there is only one number of the slope. Can I get help on how to do this, I know the graphing part but it's kind confusing when I do not have another number. TY, full points will be awarded.
This one sort of throws me off. I am not sure if I do the m= y2-y1 over x2-x1, because there is only one number of the slope. Can I get help on how to do this, I know the graphing part but it's kind confusing when I do not have another number. TY, full points will be awarded.
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You want the line with slope -6 that passes through (2,-1):
You are given the slope, you don't have to calculate it.
y = mx + b : m is given as -6
y = -6x + b : you are given that a point on the line is (2,-1)
(-1) = -6(2) + b
-1 + 12 = b
b = 11
The desired line is:
y = -6x + 11
You are given the slope, you don't have to calculate it.
y = mx + b : m is given as -6
y = -6x + b : you are given that a point on the line is (2,-1)
(-1) = -6(2) + b
-1 + 12 = b
b = 11
The desired line is:
y = -6x + 11
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OK so if you have graph paper, very easy!!! The Y slope is the vertical, the X is horz. Now start at 0,0, then go to the right two times and go down once. Now go up six times, and then go to the left once! Repeat, draw a line, DONE! :D hoped this helped!