Math problem help please

2 (3y - 1) - 4y = 2

i did it wrong

Okay well first you distribute.
2 (3y - 1) - 4y = 2

6y - 2 - 4y = 2

Then you combine like terms

2y - 2 = 2

You then add 2 to both sides, the +2 canceling out the -2..

2y=4

You then divide by 2 on both sides...

and sooo y = 2

2(3y-1)-4y=2<-----Original equation
2*3y-2*1-4y=2<------Multiply 2 by (3y-1)
6y-2-4y=2<------Equation after
2y-2=2<-----Combine like terms (6y-4y=2y)
2y=4<-----Move -2 to other side to leave y on one side
y=2<----Divide by 2 for each side

6y-2-4y=2..get rid of brackets...combine like terms
2y-2=2 add 2 to both sides
2y=4 divide by 2
y=2.. ck 2(6-1)-4*2=2 5(2)-8=2 y= 2 is correct

First you should break down the brackets. Then group similar terms.

2 ( 3y - 1 ) - 4y = 2
6y - 2 - 4y = 2
2y - 2 = 2
2y = 2 + 2
2y = 4
y = 2

Good luck~

2(3y - 1) - 4y = 2

6y - 2 - 4y = 2

2y = 2 + 2

2 y = 4

y = 4/2

y = 2

2 (3y - 1) - 4y = 2
6y - 2 - 4y = 2
2y - 2 = 2
2y = 4
y = 2

I think:

2(3y-1)-4y=2
[(2x3y)-(2x1)] -4y=2
[6y-2] -4y=2
6y-2-4y=2
6y-4y-2=2
2y-2=2
+2 +2
2y=4
y= 4/2
y=2