Limit to compute f '3 f(x) x^2 -2x +3

help math pleaseeeeeeeeeeeeee 10 points

f'(x) = 2x - 2
f'(3) = 2(3) - 2 = 6 - 2 = 4

lim(h-->0) [f(x+h) - f(x)] / h
lim(h-->0) [(x+h)^2-2(x+h)+3-(x^2-2x+3)] / h
lim(h-->0) [x^2+2xh+h^2-2x-2h+3-x^2+2x-3]/h
lim(h-->0) [h^2+2xh-2h]/h
lim(h-->0) h + 2x - 2
f'(x) = 2x-2
f'(3) = 2(3) - 2 = 6 - 2 = 4

Better? :)

sub f'3 in for x wherever you see it so

f(3)= 3^2 - 2(3) +3
so
9-6+3=0

0 is the answer!!

also wolframalpha.com is a great site for all problems (math,physics,calc,engineering...)