How would you simplify this? Algebra 2

[From: ] [author: ] [Date: 11-11-16] [Hit: ]

And please explain how to do it... thanks so much-Its just like multiplying binomials. Using FOIL,(-1 + 5i)(4 - 3i) = (-1)(4) + (-1)(-3i) + (5i)(4) + (5i)(-3i) = -4 + 3i + 20i + 15= 11 + 23i-multiply by foiling and you should get your answer.......

I'm working with imaginary numbers...which means i^2=-1
Simplify:
(1+i)(2+3i)(4-3i)

And please explain how to do it... thanks so much

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It's just like multiplying binomials. Using FOIL,

(1 + i)(2 + 3i) = (1)(2) + (1)(3i) + (i)(2) + (i)(3i)
= 2 + 3i + 2i + (-3)
= -1 + 5i

(-1 + 5i)(4 - 3i) = (-1)(4) + (-1)(-3i) + (5i)(4) + (5i)(-3i)
= -4 + 3i + 20i + 15
= 11 + 23i

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multiply by foiling and you should get your answer.

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keywords: would,you,How,simplify,this,Algebra,How would you simplify this? Algebra 2

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