What is the initial velocity

An object travels 200 meters at an acceleration of 6 m/s until it reaches a velocity of 70 m/s. What is the initial velocity?

Use the formula v^2 = v0^2 + 2ad, where v is the final velocity, v0 is the initial velocity, a is the acceleration, and d is the distance.

In this problem, v is 70, a is 6, and d is 200, so we have:
v^2 = v0^2 + 2ad
70^2 = v0^2 + 2*6*200
v0^2 + 2400 = 4900
v0^2 = 2500
v0 = 50

So, the initial velocity is 50 m/s.

Hope that helps :)

Edit:
Oops, the square root of 2500 is 50, not 500. Fixed.

I'll assume acceleration is 6 m/s^2.

the equation to use here is v^2 = vi^2 + 2ad, where vi is initial velocity, v is final velocity, d is distance, and a is acceleration. This is the equation of motion without the time variable in it. substitution yields...

70^2 = vi^2 + 2*6*200
4900 = vi^2 + 2400
vi^2 = 2500
vi = 50 m/s

on a side note.... it's interesting that 2 Matt's answered with 2 very similar answers!

what's the distance