I Need Help With a Pre-Calculus Questions
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I Need Help With a Pre-Calculus Questions

[From: ] [author: ] [Date: 11-12-25] [Hit: ]
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1) let x^2 = y
f(x) = 2y^2 - 3y - 2
0 = 2y^2 - 3y - 2
(2y + 1)(y - 2) = 0
y = -1/2, 2
x^2 = -1/2, 2
x = ±√2
= (b) ±1.4

2) 2/x > -1/x-1
2x - 2 > -x
3x > 2
x > 2/3
i think you wrote part 2 wrong, or i just made a mistake, not sure

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1st ans is +sq. root of 2 and -square root of 2

2nd ans is d
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