Factor x^2+x^2-4 please

[From: ] [author: ] [Date: 12-02-18] [Hit: ]

2.roots at x = { -2, 0, 2 }-1.2.2(x^2 - 2)-factors of x^2 + x^2 - 4 would be 2x^2 - 4,......

Factorization to solve this. Need it to find the points of intersection for the question

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x^2+x^2-4
= 2x^2 -4
= 2(x^2 -2)
= 2(x - sqrt2)( x + sqrt 2)

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x^2+x^2-4
= 2x^2 -4
= 2(x^2 -2)
= 2[x - sqrt(2)] [ x + sqrt (2)] Ans.

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1. Add the like terms together

2x^2 - 4

2. 2 goes into both of the terms

2(x^2 - 2)

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x^2 + x^2 - 4

x^2 + ( x + 2 )(x - 2)

roots at x = { -2, 0, 2 }

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1.2x^2 - 4

2.2(x^2 - 2)

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factors of x^2 + x^2 - 4 would be 2x^2 - 4, so the factors would be 2x and x - 2

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x^2+x^2-4
=2x^2-4
=2(x^2-2)
=2(x-square root 2)(x+square root 2)

1

keywords: please,Factor,Factor x^2+x^2-4 please

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