Can someone please help me with these math problems

Hey everyone.
Could you please help me with these problems?
And please explain step by step because i am so confused.

1. The product of two consecutive even integers is 16 more than 8 times the smaller interger. Determine the intergers.
- I keep trying but i keep getting it wrong.

2. The area of a square is tripled by adding 10 cm to one dimension and 12 cm to the other. Determine the side length of the square

3. Tom plans to build a uniform walkway around a rectangular flower bed that is 20m by 40m. There is enough material to make a walkway that has a total area of 700m2. What is the width of the walkway?

Thank so much! Please explain as i am completely lost. Thanks!

1. x,x+2 two consecutive even integers,
then x(x+2)=16+8x <==>
x^2+2x=16+8x <==>
x^2-6x-16=0

Solving we get x=10 orx=-2
So the integers are
(8,10) or(-2,0)

2. Let's name x the square's side .
Then square's area is
A=x^2
After changes we get a
rectangular with area
B=(x+10)(x+12) .So
3A=B <==>
3x^2=(x+10)(x+12) <==>
3x^2=x^2+22x+120 <==>
2x^2-22x-120=0
Solving we get
x=15 or
x=-4 (not acceptable<0)

3. The area of the
rectangular flower bed is
20*40=800.
Assuming that x is the
walkway's width then,
The new rectangular's
area is (20+2x)(40+2x).
Now the path's area is
(20+2x)(40+2x)-800=700
800+80x+40x+4x^2-800=700

4x^2+120x-700=0

x^2-30x-175=0

solving....

x=35 or
x=-5<0 (not acceptable)

cheers!