Algebra 2, Stuck on this problems! :(
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Algebra 2, Stuck on this problems! :(

[From: ] [author: ] [Date: 12-04-04] [Hit: ]
8, 27, x^3, etc.......
What is the simplest form of: (power of 3)√25xy(power of 2) multiplied by (power of 3)√15x(power of 2)

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^3√(25xy^2) * ^3√(15x^2)
^3√(375x^3y^2)
5x*^3√(3y^2) <--- final answer

Hope this helps!

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I am assuming that by (power of 3)√25xy you mean the cubed root of (25xy) or ∛(25xy)

∛[25xy]*∛[15x^2]

Since they are both cubed roots, and everything is multiplied, you can simply combine them under one radical.

∛[25*x*y*15*x^2] =
∛[3*125*x^3*y =
∛[125]*∛[x^3]*∛[3y] =
5x*∛[3y]

If you are dealing with a cubed root like this, you need to try to factor out even cubes,

1, 8, 27, x^3, etc.

I hope this helps

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(power of 3)√25xy(power of 2) multiplied by (power of 3)√15x(power of 2) =

= [√25xy]^3/2 * [√15x]^3/2 = [(√25 * √15)x^2y]^3/2 =

= [√375x^2y]^3/2 >============================< ANSWER
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