Hi I need help with the following.
f(x)=6x-x^2
Find the derivative using the definition of the derivative.
I know the formula is limit of[ f(x+h)-f(x)]/h as h approaches 0. And I know the derivative of f(x) is 6-2x
but I'm not getting the right answer. I'm having trouble with f(x+h) I can't seem to get it right..
If someone can tell me what f(x+h) is, I can do the rest from there. Thanks in advance
f(x)=6x-x^2
Find the derivative using the definition of the derivative.
I know the formula is limit of[ f(x+h)-f(x)]/h as h approaches 0. And I know the derivative of f(x) is 6-2x
but I'm not getting the right answer. I'm having trouble with f(x+h) I can't seem to get it right..
If someone can tell me what f(x+h) is, I can do the rest from there. Thanks in advance
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Ok, well if the original equation is:
f(x) = 6x-x^2
you treat f(x+h) as you would any other value
for example, if you wanted to find f(2), it would be:
f(2) = 6(2)-(2)^2 = 8
So, f(x-h) would be:
f(x-h) = 6(x-h)-(x-h)^2
f(x) = 6x-x^2
you treat f(x+h) as you would any other value
for example, if you wanted to find f(2), it would be:
f(2) = 6(2)-(2)^2 = 8
So, f(x-h) would be:
f(x-h) = 6(x-h)-(x-h)^2
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f(x+h) means that where ever you have "x", replace it with the whole "x+h" so then 6x-x^2 would become s(x+h)-(x+h)^2..so plug that in the formula and solve it..If you still can't, come back here and I'll help you with it!!!