Why is the (ln lil) = 0

if you take the square root of i^2 + 0^2, dont you still get ln i?

To get the magnitude of x + iy, you take sqrt(x^2 + y^2), NOT sqrt(x^2 + (iy)^2).

so |i| = | 0 + 1i | = sqrt(0^2 + 1^2) = sqrt(1).

Does that help?

no.....
i^2+0^2 = 1 ( since i^2 is 1 and 0^2 = 0 so 1+0 = 1)
and also the square root is 1 so der will bi no '' i '' in the answer........
hope u got it.....

|i|=1 so ln|i| =0.