Area under a curve trapezoidal method

The height of the trapezoid is 1 and the curve has the equation, y=5x²

How do I figure this out? I'm sorry if this is a stupid question.

it's not a stupid question at all

well first you need a boundary.
let's say that the boundary is from x=0 to x=5
when x=0, y=0
x=1, y=5
x=2, y=20
x=3, y=45
x=4, y=80
x=5, y=125

the area of a trapezoid is (.5)(height)(base1+base2)
the height is going to be 1 as you stated
and the bases are the y values at each x value

so the area of the first trapezoid is (.5)(1)(0+5)
are of the second trapezoid is (.5)(1)(5+20)
(.5)(1)(20+45)
(.5)(1)(45+80)
(.5)(1)(80+125)

if you factor out the (.5)(1), you'll end up with: (.5)(1)[0+5+5+20+20+45+45+80+80+125]
or
(.5)(1)[0+2(5)+2(20)+2(45)+2(80)+125]
or
(.5)(1)[0+2(5+20+45+80)+125]

so all in all, you'll have (.5)(height)[(first y value)+2(sum of middle y values)+(last y value)]

no matter what your boundary is, you'll have the same basic form as above.
hope this helps !