How to FOIL with 3 terms?
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How to FOIL with 3 terms?

[From: ] [author: ] [Date: 12-05-19] [Hit: ]
and take it carefully in order, you wont need to rely on a crutch like FOIL, which just does the tracking for you:first terms, outer terms, inner tems, last terms just makes sure you hit all the combinations.......
I have to answer this question but I never learned how to foil using 3 terms :S

This is the question : (2x+5)(3x-2)=(x+1)

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FOIL is just a handy way to keep track of multiplying a couple of binomials.
What you are really doing is just applying the distribute law to the product of two sums.
If you have (a + b + c)(D + E) just apply each term in the first to each term in the second:
(a + b + c)(D + E) =
aD + aE + bD + bE + cD + dE.

You are multiplying 3 terms by 2 terms. Just make sure you end up with 3x2 = 6 terms.

If you keep track of what you've multiplied, and take it carefully in order, you won't need to rely on a crutch like FOIL, which just does the tracking for you: first terms, outer terms, inner tems, last terms just makes sure you hit all the combinations. It's not a sophisticated mathematical formula, so you don't need a complicated extension of it to handle 3x2 terms.

Your statement "I never learned how to foil using 3 terms" tells me that your teacher just taught you a mechanical rule without explaining what it was about or why it worked, so a little complication like adding another term leaves you confused. Shame on your teacher.

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You need to foil two terms first, then foil the other one in
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