Help solving for a radical

solve: radical of x+23 = x+11

I was totally stumped by this so could someone help me?

Making assumptions about where parentheses should be,
√(x + 23) = x + 11
(√(x + 23))^2 = (x + 11)^2
x + 23 = x^2 + 22x + 121
0 = x^2 + 21x + 98
0 = (x + 14)(x + 7)
x = -14 or x = -7
Discard x = -14 because it is an extraneous solution resulting from squaring both sides of the equation, leaving just
x = -7

I think you want to solve √(x + 23) = x + 11.

If so, x + 23 = x^2 + 22x + 121
0 = x^2 + 21x - 98
x ≈ 3.93 or x ≈ -24.93