Math problem... s+(8/s)=-9

Need help solving this. Not just an answer, but I need to know steps. Please help!

multiply through by s to eliminate the rational function. {Be warned, you need to remember s cant = 0}

s^2 + 8 = -9s

s^2 + 9s + 8 = 0

(s+8)(s+1) = 0 {s not equal 0}

s = -8 or -1

Since neither of these is 0, these are both answers.

I hope this helps

s + (8/s) = -9

turn the sole s into a fraction

s²/s + 8/s = -9

combine the fractions

(s² + 8)/s = -9

multiply the whole thing by s to get rid of the fraction

s² + 8 = -9s

add 9s to both sides

s² + 9s + 8 = 0

now it just looks like a quadratic... factor and solve

(s + 8)(s + 1) = 0
s = -1, s = -8

okay so first we need to multiply the whole equation by s giving...

s^2 + 8 = -9s

now rearranging gives us a quadratic

s^2 + 9s + 8 = 0

Factorising the quadratic gives us

(s+8)(s+1)=0

Hence either s+8 equals 0 or s+1 equals 0.

Now can you work out the two possible values of s?

s+(8/s)=-9,
multiply by s,
s^2+8=-9s,
s^2-(-9s)+8=0,
s^2+9s+8=0,
factor,
(s+1)(s+8)=0,
s+1=0, s+8=0,
s=-1, -8.
Answer: s=-1, -8.

s + 8/s = -9
s^2 + 8 = -9s
s^2 + 9s + 8 = 0
s^2 + s + 8s + 8 = 0
s(s + 1) + 8(s + 1) = 0
(s + 1)(s + 8) = 0
=> s + 1 = 0, s = -1
=> s + 8 = 0, s = -8
s ∈ {-8,-1}

first step:ask
second step:bill
third step:cosby