I have a hard time rearranging equations because I think I got it but it turns out to be super wrong so can anyone good at this please help me? :) I provided the answers in the picture below I just don't know how to get to those answers I keep getting things completely different like for 7a i got a = (x+y+z) / (bc)
http://i1253.photobucket.com/albums/hh58…
http://i1253.photobucket.com/albums/hh58…
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7a. Multiply both sides by abc:
xbc + acy + abz = abc
Factor out an a in each term that has one:
xbc + a(cy) + a(bz) = a(bc)
Get them all on the same side of the equation, and away from everything else:
xbc = a(bc) - a(cy) - a(bz)
Combine the terms on the right:
xbc = a(bc - cy - bz)
Divide both sides by (bc - yc - zb) to isolate a: xbc/(bc - yc - zb) = a
7b. Distribute the 2 inside the parentheses:
V = 2ab + 2bc + 2ca
Get everything without an a on the other side of the equation:
V - 2bc = 2ab + 2ca
Factor out an a on the right:
V - 2bc = a(2b + 2c)
Divide both sides by (2b + 2c); (V - 2bc)/(2b + 2c) = a; if you factor out a 2 in the denominator, it will look the same as the given answer.
d. Factor out a P from both terms on the right:
A = P(1 + nr)
Divide both sides by (1 + nr); P = A/(1 + nr).
xbc + acy + abz = abc
Factor out an a in each term that has one:
xbc + a(cy) + a(bz) = a(bc)
Get them all on the same side of the equation, and away from everything else:
xbc = a(bc) - a(cy) - a(bz)
Combine the terms on the right:
xbc = a(bc - cy - bz)
Divide both sides by (bc - yc - zb) to isolate a: xbc/(bc - yc - zb) = a
7b. Distribute the 2 inside the parentheses:
V = 2ab + 2bc + 2ca
Get everything without an a on the other side of the equation:
V - 2bc = 2ab + 2ca
Factor out an a on the right:
V - 2bc = a(2b + 2c)
Divide both sides by (2b + 2c); (V - 2bc)/(2b + 2c) = a; if you factor out a 2 in the denominator, it will look the same as the given answer.
d. Factor out a P from both terms on the right:
A = P(1 + nr)
Divide both sides by (1 + nr); P = A/(1 + nr).
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Question # 7 Part a.)
x/a + y/b + z/c = 1 [solve for 'a']
x/a + y/b + z/c = 1
Get the term with 'y' and 'z' to the other side
x/a = 1 - y/b - z/c
Get the terms on the right under the same denominator
x/a =[bc - cy - bz] / bc
Divide both sides by 'x'
1/a = [bc - cy - bz] / (bc)x
Now take the reciprocal of both sides (raise both sides to the "-1" power) to get
a = (bc)x / [bc - cy - bz]
x/a + y/b + z/c = 1 [solve for 'a']
x/a + y/b + z/c = 1
Get the term with 'y' and 'z' to the other side
x/a = 1 - y/b - z/c
Get the terms on the right under the same denominator
x/a =[bc - cy - bz] / bc
Divide both sides by 'x'
1/a = [bc - cy - bz] / (bc)x
Now take the reciprocal of both sides (raise both sides to the "-1" power) to get
a = (bc)x / [bc - cy - bz]
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x/a + y/b + z/c = 1
(bcx + acy + abz) / abc = 1 .. (Find LCD and add terms on left side)
bcx + acy + abz = abc ......... (Multiply both sides by abc)
abz + acy - abc = - bcx ........ (Subtract abc and bcx from both sides)
a(bz + cy - bc) = - bcx ......... (Factor out a from left side)
a = - bcx / (bz + cy - bc) ...... (Divide both sides by bz - cy - bc)
a = bcx / (bc - cy - bz) ........ (Multiply numerator and denominator by - 1 and rearrange denominator)
Answer: Option a.
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(bcx + acy + abz) / abc = 1 .. (Find LCD and add terms on left side)
bcx + acy + abz = abc ......... (Multiply both sides by abc)
abz + acy - abc = - bcx ........ (Subtract abc and bcx from both sides)
a(bz + cy - bc) = - bcx ......... (Factor out a from left side)
a = - bcx / (bz + cy - bc) ...... (Divide both sides by bz - cy - bc)
a = bcx / (bc - cy - bz) ........ (Multiply numerator and denominator by - 1 and rearrange denominator)
Answer: Option a.
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Its simple
you have,
x/a + y/b +z/c = 1
x/a = 1 - y/b - z/c
Taking LCM
x/a = bc - yc - zb / (bc)
1/a = bc - yc - zb / (bcx)
a = bcx / bc - yc - zb
a = bcx / bc - bz - cy
Answer
you have,
x/a + y/b +z/c = 1
x/a = 1 - y/b - z/c
Taking LCM
x/a = bc - yc - zb / (bc)
1/a = bc - yc - zb / (bcx)
a = bcx / bc - yc - zb
a = bcx / bc - bz - cy
Answer