How would you solve this 2(x-3)^2

Thanks

2(x^2 +9 -6x)
2x^2 +18-12x

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Expanding the polynomial gives me:

2(x-3)² = 2(x² - 6x +9)
= 2x² - 12x + 18

2x-6)^2= (2x-6)(2x-6) =4x^2-12x-12x+36= 4x^2-24x+36
= 4(x^2-6x+9 then factor x-3 x-3 x=3
plug x in 3-3 =0 2(0)^2 = 0