Can you find the limit

lim[x:0,arcsin(7x)/ (3x)]
It says the arcsin(7x) all over 3x . As x approaches to zero.

Can you show the steps? Thanks.

arcsin(7x) / 3x

(7x/7x) arcsin(7x) / 3x

(7x/3x) arcsin(7x) / 7x

(7/3)(1) = 7/3

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