Find f. f '(x) = 5 / √( 1 − x2), f(1/2) = 5 antiderivative

Find f.
f '(x) = 5 / √( 1 − x2), f(1/2) = 5

f(x) = ?

f'(x)=5/√(1-x²)
f(x)=5Arcsinx+C

f(1/2)=5
5π/6+C=5
C=5-5π/6

f(x)=5Arcsinx+5-5π/6

f(x) = 5sin^-1(x) + C
f(1/2) = 5sin^-1(1/2) + C = 5
5*pi/6 + C = 5
C = 5-5pi/6
f(x) = 5sin^-1(x) + 5 -5pi/6