A rock weighing 8654 N rock with a volume of 36 L is completely submerged in mercury. The density of mercury is 13.6 kg/L.
How do I calculate the buoyant force of a rock if the density is 24.529 kg/L. ??
How do I calculate the buoyant force of a rock if the density is 24.529 kg/L. ??
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The rock displaces 36 L of mercury at a density of 13.6 kg/L
36*13.6 = 489.6 kg of mercury displaced
489.6 x 9.8 = 4798 N of upward force on the rock from the buoyant forces of the liquid mercury.
Net force on the rock is 8654-4798 = 3856 N downward.
36*13.6 = 489.6 kg of mercury displaced
489.6 x 9.8 = 4798 N of upward force on the rock from the buoyant forces of the liquid mercury.
Net force on the rock is 8654-4798 = 3856 N downward.