Help me with this physics exercise
http://subefotos.com/ver/?a16b02ac5b93a1d6eb029c2d86661e29o.jpg
The answer is 45 seconds but I do not know how to solve it
http://subefotos.com/ver/?a16b02ac5b93a1d6eb029c2d86661e29o.jpg
The answer is 45 seconds but I do not know how to solve it
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Hello
you can not mean that the answer is 45 seconds.
The weight sinks down by 0,2 m when connected to the spring. And the spring constants are simply additive. One spring pushes, the other pulls with the same force.
So you can find k for the system: k = N/s = 0,5*9,81/0,2 -->
k = 24,52 N/m
And now you can find the period time by
T = 2pi√(m/k) = 2pi*√(0,5/24,52)
T = 0,897 seconds.
Since it takes 1/2 period time to reach the top point, the time needed is 0,897/2 s
= 0,4485 seconds.
This sounds much better than 45 seconds.
Regards
you can not mean that the answer is 45 seconds.
The weight sinks down by 0,2 m when connected to the spring. And the spring constants are simply additive. One spring pushes, the other pulls with the same force.
So you can find k for the system: k = N/s = 0,5*9,81/0,2 -->
k = 24,52 N/m
And now you can find the period time by
T = 2pi√(m/k) = 2pi*√(0,5/24,52)
T = 0,897 seconds.
Since it takes 1/2 period time to reach the top point, the time needed is 0,897/2 s
= 0,4485 seconds.
This sounds much better than 45 seconds.
Regards