Rotation and speed problem
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# Rotation and speed problem

[From: ] [author: ] [Date: 11-05-18] [Hit: ]
94 ÷ π = 2.Diameter = ([(50,......
A lift travellig at a constant speed of 50km/hour has a winding drum for the lift cable which rotates at 105rpm what is the diameter of the winding drum?

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A lift traveling at a constant speed of 50km/hour has a winding drum for the lift cable which rotates at 105rpm what is the diameter of the winding drum?

In 1 hour, the lift cable, which is attached to the lift, moves 50 km = 50,000 meters.

In 1 minute, the lift cable moves 50,000 ÷ 60 = 833⅓ meters

In that same minute, the winding drum rotates 105 revolutions.
105 revolutions = 833⅓ meters
1 revolution = 833⅓ ÷ 105 = 7.94 m

1 revolution = 1 circumference = 2 * π * radius = π diameters

7.94 m = π diameters
1 diameter = 7.94 ÷ π = 2.53 m

Without rounding:

Diameter = ([(50,000 m/hr ÷ 60 min/hr) ÷ 105rev/min] ÷ π diameters/rev) meters per diameter
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