What is the magnitude of the average force on the target
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What is the magnitude of the average force on the target

[From: ] [author: ] [Date: 11-08-09] [Hit: ]
Discipline yourself to use units.Under the above assumptions,F = 1/2 mv^2 / s = (1/2 * 0.013 kg * 130^2) / 0.......
At a shooting competition, a contestant fires and a 13.0 bullet leaves the rifle with a muzzle speed of 130 . The bullet hits the thick target backing and stops after traveling 4.10 .

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bullet = 13gm
muzzle speed = 130 m/s
travel depth = 4.1 cm
I hope that's what you meant. Discipline yourself to use units.

Under the above assumptions,
1/2 mv^2 = F*s
F = 1/2 mv^2 / s = (1/2 * 0.013 kg * 130^2) / 0.041m = 2679N
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