Tammy leaves the office, drives 39 km due
north, then turns onto a second highway and
continues in a direction of 33 degree north of east
for 92 km.
What is her total displacement from the
office?
Answer in units of km.
At what angle is her displacement? (Consider
east to be 0degree and north 90deg.)
Answer in units of deg.
north, then turns onto a second highway and
continues in a direction of 33 degree north of east
for 92 km.
What is her total displacement from the
office?
Answer in units of km.
At what angle is her displacement? (Consider
east to be 0degree and north 90deg.)
Answer in units of deg.
-
Displacement in North = 39 + 92sin33* = 89.11 km
Displacement in East = 92cos33* = 77.16 km
=>Displacement(net) = √[(89.11)^2 + (77.16)^2] = 117.87 km
=>By tanθ = 89.11/77.16 = 1.15 = tan49*
=>θ = 49* North of East
Displacement in East = 92cos33* = 77.16 km
=>Displacement(net) = √[(89.11)^2 + (77.16)^2] = 117.87 km
=>By tanθ = 89.11/77.16 = 1.15 = tan49*
=>θ = 49* North of East