Physics help! Derive Kepler's third law
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Physics help! Derive Kepler's third law

[From: ] [author: ] [Date: 11-08-25] [Hit: ]
R / t^2=G Ms .R^3 / T^2= G .......
r^3/t^2=GM/4pi^2

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Centripetal force on the Earth ( or any planet ) = Me . v^2 / R

v = 2πR / T

Centripetal force = Me . 4π^2 . R^2 / R . T^2 = Me . 4π^2 . R / T^2

Centripetal force is supplied by the gravitational attraction between the Sun and the Earth

Me . 4π^2 . R / t^2 = G Ms . Me / R^2

Me cancels

R^3 / T^2 = G . Ms / 4 π^2
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