Drops of rain fall perpendicular to the roof of a parked car during a rainstorm. The drops strike the roof with a speed of 11 m/s, and the mass of rain per second striking the roof is 0.075 kg/s.
(a) Assuming the drops come to rest after striking the roof, find the average force exerted by the rain on the roof.
(a) Assuming the drops come to rest after striking the roof, find the average force exerted by the rain on the roof.
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F = m a which has units of kgm/s^2
notice that if we multiply 11m/s x 0.075kg/s we have units also of kgm/s^2 and this product is the average force acting on the roof
notice that if we multiply 11m/s x 0.075kg/s we have units also of kgm/s^2 and this product is the average force acting on the roof
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It's inversely proportional to the amount of dirt on the roof of the car.
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(11m/s)(.075kg/s)
.825kg*m/s^2=F
F=.825 N
.825kg*m/s^2=F
F=.825 N